Regex for AWS S3 Bucket Name
Regex Pattern
^[a-z0-9][a-z0-9.-]{1,61}[a-z0-9]$Valid AWS S3 bucket name (3-63 chars, lowercase)
Quick Answer
The regex pattern for aws s3 bucket name is `^[a-z0-9][a-z0-9.-]{1,61}[a-z0-9]$`. Valid AWS S3 bucket name (3-63 chars, lowercase). This works in JavaScript, Python, Ruby, PHP, Java, and most regex engines that support PCRE syntax.
Test Examples
| Input | Result |
|---|---|
| my-bucket | ✓ Matches |
| example.bucket.2024 | ✓ Matches |
| data-lake-prod | ✓ Matches |
| -bucket | ✗ No match |
| UPPERCASE | ✗ No match |
| a | ✗ No match |
| bucket-with--double-dash | ✗ No match |
Code Examples
javascript
const regex = /^[a-z0-9][a-z0-9.-]{1,61}[a-z0-9]$/;
const isValid = regex.test(value);python
import re
pattern = r'^[a-z0-9][a-z0-9.-]{1,61}[a-z0-9]$'
if re.match(pattern, value):
print("valid")ruby
pattern = /^[a-z0-9][a-z0-9.-]{1,61}[a-z0-9]$/
if value =~ pattern
puts "valid"
endphp
if (preg_match('/^[a-z0-9][a-z0-9.-]{1,61}[a-z0-9]$/', $value)) {
echo "valid";
}java
String pattern = "^[a-z0-9][a-z0-9.-]{1,61}[a-z0-9]$";
boolean isValid = value.matches(pattern);Frequently Asked Questions
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