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Regex for Date MM/DD/YYYY

Regex Pattern

^(0[1-9]|1[0-2])\/(0[1-9]|[12]\d|3[01])\/\d{4}$

US date format with slashes (MM/DD/YYYY)

Quick Answer

The regex pattern for date mm/dd/yyyy is `^(0[1-9]|1[0-2])\/(0[1-9]|[12]\d|3[01])\/\d{4}$`. US date format with slashes (MM/DD/YYYY). This works in JavaScript, Python, Ruby, PHP, Java, and most regex engines that support PCRE syntax.

Test Examples

InputResult
04/11/2026✓ Matches
01/01/2000✓ Matches
12/31/1999✓ Matches
4/11/2026✗ No match
13/01/2026✗ No match
2026-04-11✗ No match

Code Examples

javascript

const regex = /^(0[1-9]|1[0-2])\\/(0[1-9]|[12]\d|3[01])\\/\d{4}$/;
const isValid = regex.test(value);

python

import re
pattern = r'^(0[1-9]|1[0-2])\/(0[1-9]|[12]\d|3[01])\/\d{4}$'
if re.match(pattern, value):
    print("valid")

ruby

pattern = /^(0[1-9]|1[0-2])\/(0[1-9]|[12]\d|3[01])\/\d{4}$/
if value =~ pattern
  puts "valid"
end

php

if (preg_match('/^(0[1-9]|1[0-2])\\/(0[1-9]|[12]\d|3[01])\\/\d{4}$/', $value)) {
    echo "valid";
}

java

String pattern = "^(0[1-9]|1[0-2])\\/(0[1-9]|[12]\\d|3[01])\\/\\d{4}$";
boolean isValid = value.matches(pattern);

Frequently Asked Questions

Related Regex Patterns

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