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Regex for Date YYYY-MM-DD

Regex Pattern

^\d{4}-(0[1-9]|1[0-2])-(0[1-9]|[12]\d|3[01])$

ISO 8601 date format

Quick Answer

The regex pattern for date yyyy-mm-dd is `^\d{4}-(0[1-9]|1[0-2])-(0[1-9]|[12]\d|3[01])$`. ISO 8601 date format. This works in JavaScript, Python, Ruby, PHP, Java, and most regex engines that support PCRE syntax.

Test Examples

InputResult
2026-04-11✓ Matches
2000-01-01✓ Matches
1999-12-31✓ Matches
2026/04/11✗ No match
26-04-11✗ No match
2026-13-01✗ No match
2026-04-32✗ No match

Code Examples

javascript

const regex = /^\d{4}-(0[1-9]|1[0-2])-(0[1-9]|[12]\d|3[01])$/;
const isValid = regex.test(value);

python

import re
pattern = r'^\d{4}-(0[1-9]|1[0-2])-(0[1-9]|[12]\d|3[01])$'
if re.match(pattern, value):
    print("valid")

ruby

pattern = /^\d{4}-(0[1-9]|1[0-2])-(0[1-9]|[12]\d|3[01])$/
if value =~ pattern
  puts "valid"
end

php

if (preg_match('/^\d{4}-(0[1-9]|1[0-2])-(0[1-9]|[12]\d|3[01])$/', $value)) {
    echo "valid";
}

java

String pattern = "^\\d{4}-(0[1-9]|1[0-2])-(0[1-9]|[12]\\d|3[01])$";
boolean isValid = value.matches(pattern);

Frequently Asked Questions

Related Regex Patterns

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